From 88c9e761cbe3a8242a6c9056e093f8bc4d91c81b Mon Sep 17 00:00:00 2001
From: 0xff-dev <stevenshuang521@gmail.com>
Date: Fri, 5 Sep 2025 09:09:01 +0800
Subject: [PATCH] Add solution and test-cases for problem 2749

---
 .../README.md                                 | 33 +++++++++++++++++
 .../Solution.go                               | 35 +++++++++++++++++--
 .../Solution_test.go                          | 21 ++++++-----
 3 files changed, 76 insertions(+), 13 deletions(-)
 create mode 100644 leetcode/2701-2800/2749.Minimum-Operations-to-Make-the-Integer-Zero/README.md

diff --git a/leetcode/2701-2800/2749.Minimum-Operations-to-Make-the-Integer-Zero/README.md b/leetcode/2701-2800/2749.Minimum-Operations-to-Make-the-Integer-Zero/README.md
new file mode 100644
index 000000000..991e71e4a
--- /dev/null
+++ b/leetcode/2701-2800/2749.Minimum-Operations-to-Make-the-Integer-Zero/README.md
@@ -0,0 +1,33 @@
+# [2749.Minimum Operations to Make the Integer Zero][title]
+
+## Description
+You are given two integers `num1` and `num2`.
+
+In one operation, you can choose integer `i` in the range `[0, 60]` and subtract `2^i + num2` from `num1`.
+
+Return the integer denoting the **minimum** number of operations needed to make `num1` equal to `0`.
+
+If it is impossible to make `num1` equal to `0`, return `-1`
+
+**Example 1:**
+
+```
+Input: num1 = 3, num2 = -2
+Output: 3
+Explanation: We can make 3 equal to 0 with the following operations:
+- We choose i = 2 and subtract 22 + (-2) from 3, 3 - (4 + (-2)) = 1.
+- We choose i = 2 and subtract 22 + (-2) from 1, 1 - (4 + (-2)) = -1.
+- We choose i = 0 and subtract 20 + (-2) from -1, (-1) - (1 + (-2)) = 0.
+It can be proven, that 3 is the minimum number of operations that we need to perform.
+```
+
+**Example 2:**
+
+```
+Input: num1 = 5, num2 = 7
+Output: -1
+Explanation: It can be proven, that it is impossible to make 5 equal to 0 with the given operation.
+```
+
+[title]: https://leetcode.com/problems/minimum-operations-to-make-the-integer-zero
+[me]: https://github.com/kylesliu/awesome-golang-algorithm
diff --git a/leetcode/2701-2800/2749.Minimum-Operations-to-Make-the-Integer-Zero/Solution.go b/leetcode/2701-2800/2749.Minimum-Operations-to-Make-the-Integer-Zero/Solution.go
index d115ccf5e..6b0d1bb1b 100755
--- a/leetcode/2701-2800/2749.Minimum-Operations-to-Make-the-Integer-Zero/Solution.go
+++ b/leetcode/2701-2800/2749.Minimum-Operations-to-Make-the-Integer-Zero/Solution.go
@@ -1,5 +1,36 @@
 package Solution
 
-func Solution(x bool) bool {
-	return x
+import (
+	"math/bits"
+)
+
+func canBeSumOfPowersOfTwo(n int64, k int64) bool {
+	// 1. 如果 n < k，则无法组成。因为每个 2^i 至少是 1 (2^0)。
+	if n < k {
+		return false
+	}
+
+	// 2. 计算 n 的二进制表示中 1 的个数，即所需的最小 2^i 数量。
+	minK := int64(bits.OnesCount64(uint64(n)))
+
+	// 3. 检查 k 是否在 [minK, n] 范围内。
+	// 任何在 minK 和 n 之间的 k 值都是可达的，
+	// 因为每次拆分一个 2^i 都会让总数增加 1，直到达到 n。
+	return k >= minK && k <= n
+}
+
+func Solution(num1 int, num2 int) int {
+	// 这个可定是无法完成的
+	if num2 >= num1 {
+		return -1
+	}
+	an, bn := int64(num1), int64(num2)
+	i := int64(1)
+	for ; i < 61; i++ {
+		an -= bn
+		if canBeSumOfPowersOfTwo(an, i) {
+			return int(i)
+		}
+	}
+	return -1
 }
diff --git a/leetcode/2701-2800/2749.Minimum-Operations-to-Make-the-Integer-Zero/Solution_test.go b/leetcode/2701-2800/2749.Minimum-Operations-to-Make-the-Integer-Zero/Solution_test.go
index 14ff50eb4..59f649b87 100755
--- a/leetcode/2701-2800/2749.Minimum-Operations-to-Make-the-Integer-Zero/Solution_test.go
+++ b/leetcode/2701-2800/2749.Minimum-Operations-to-Make-the-Integer-Zero/Solution_test.go
@@ -9,31 +9,30 @@ import (
 func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
-		name   string
-		inputs bool
-		expect bool
+		name         string
+		nums1, nums2 int
+		expect       int
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", 3, -2, 3},
+		{"TestCase2", 5, 7, -1},
 	}
 
 	//	开始测试
 	for i, c := range cases {
 		t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
-			got := Solution(c.inputs)
+			got := Solution(c.nums1, c.nums2)
 			if !reflect.DeepEqual(got, c.expect) {
-				t.Fatalf("expected: %v, but got: %v, with inputs: %v",
-					c.expect, got, c.inputs)
+				t.Fatalf("expected: %v, but got: %v, with inputs: %v %v",
+					c.expect, got, c.nums1, c.nums2)
 			}
 		})
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }