diff --git a/leetcode/2001-2100/2012.Sum-of-Beauty-in-the-Array/README.md b/leetcode/2001-2100/2012.Sum-of-Beauty-in-the-Array/README.md index 962866445..26a532809 100755 --- a/leetcode/2001-2100/2012.Sum-of-Beauty-in-the-Array/README.md +++ b/leetcode/2001-2100/2012.Sum-of-Beauty-in-the-Array/README.md @@ -1,28 +1,41 @@ # [2012.Sum of Beauty in the Array][title] -> [!WARNING|style:flat] -> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm) - ## Description +You are given a **0-indexed** integer array nums. For each index `i` (`1 <= i <= nums.length - 2`) the **beauty** of `nums[i]` equals: + +- `2`, if `nums[j] < nums[i] < nums[k]`, for **all** `0 <= j < i` and for **all** `i < k <= nums.length - 1`. +- `1`, if `nums[i - 1] < nums[i] < nums[i + 1]`, and the previous condition is not satisfied. +- `0`, if none of the previous conditions holds. + +Return the **sum of beauty** of all `nums[i]` where `1 <= i <= nums.length - 2`. **Example 1:** ``` -Input: a = "11", b = "1" -Output: "100" +Input: nums = [1,2,3] +Output: 2 +Explanation: For each index i in the range 1 <= i <= 1: +- The beauty of nums[1] equals 2. ``` -## 题意 -> ... - -## 题解 +**Example 2:** -### 思路1 -> ... -Sum of Beauty in the Array -```go ``` +Input: nums = [2,4,6,4] +Output: 1 +Explanation: For each index i in the range 1 <= i <= 2: +- The beauty of nums[1] equals 1. +- The beauty of nums[2] equals 0. +``` + +**Example 3:** +``` +Input: nums = [3,2,1] +Output: 0 +Explanation: For each index i in the range 1 <= i <= 1: +- The beauty of nums[1] equals 0. +``` ## 结语 diff --git a/leetcode/2001-2100/2012.Sum-of-Beauty-in-the-Array/Solution.go b/leetcode/2001-2100/2012.Sum-of-Beauty-in-the-Array/Solution.go index d115ccf5e..5d3ebb88d 100644 --- a/leetcode/2001-2100/2012.Sum-of-Beauty-in-the-Array/Solution.go +++ b/leetcode/2001-2100/2012.Sum-of-Beauty-in-the-Array/Solution.go @@ -1,5 +1,29 @@ package Solution -func Solution(x bool) bool { - return x +func Solution(nums []int) int { + l := len(nums) + + leftMax := make([]int, l) + rightMin := make([]int, l) + leftMax[0] = nums[0] + for i := 1; i < l; i++ { + leftMax[i] = max(nums[i-1], leftMax[i-1]) + } + rightMin[l-1] = nums[l-1] + for i := l - 2; i >= 0; i-- { + rightMin[i] = min(rightMin[i+1], nums[i+1]) + } + ret := 0 + for i := 1; i < l-1; i++ { + lm := leftMax[i] + rm := rightMin[i] + if nums[i] > lm && nums[i] < rm { + ret += 2 + continue + } + if nums[i] > nums[i-1] && nums[i] < nums[i+1] { + ret++ + } + } + return ret } diff --git a/leetcode/2001-2100/2012.Sum-of-Beauty-in-the-Array/Solution_test.go b/leetcode/2001-2100/2012.Sum-of-Beauty-in-the-Array/Solution_test.go index 14ff50eb4..44191f824 100644 --- a/leetcode/2001-2100/2012.Sum-of-Beauty-in-the-Array/Solution_test.go +++ b/leetcode/2001-2100/2012.Sum-of-Beauty-in-the-Array/Solution_test.go @@ -10,12 +10,12 @@ func TestSolution(t *testing.T) { // 测试用例 cases := []struct { name string - inputs bool - expect bool + inputs []int + expect int }{ - {"TestCase", true, true}, - {"TestCase", true, true}, - {"TestCase", false, false}, + {"TestCase1", []int{1, 2, 3}, 2}, + {"TestCase2", []int{2, 4, 6, 4}, 1}, + {"TestCase3", []int{3, 2, 1}, 0}, } // 开始测试 @@ -30,10 +30,10 @@ func TestSolution(t *testing.T) { } } -// 压力测试 +// 压力测试 func BenchmarkSolution(b *testing.B) { } -// 使用案列 +// 使用案列 func ExampleSolution() { }