2-initials

Author: Abayie

Sprint-1/1-key-exercises/2-initials.js

@@ -6,9 +6,27 @@ let lastName = "Johnson";
 // This should produce the string "CKJ", but you must not write the characters C, K, or J in the code of your solution.
 
 
-// let initials = `${firstName.slice(0,1)}${middleName.slice(0,1)}${lastName.slice(0,1)}`;
-let initials = `${firstName.charAt(0)}${middleName.charAt(0)}${lastName.charAt(0)}`;
+// let initials = `${firstName.slice(0,1)}${middleName.slice(0,1)}${lastName.slice(0,1)}`; using slice on template literals
+
+//let initials = `${firstName.charAt(0)}${middleName.charAt(0)}${lastName.charAt(0)}`; using charAt on template literals
+
+//let initials = (firstName[0] || '') + (middleName[0] || '') + (lastName[0] || ''); using concatenation
+
+// let initials = `${firstName[0] || ''}${middleName[0] || ''}${lastName[0] || ''}` //template literals
+
+//let initials = [firstName, middleName, lastName].map(name => name.slice(0,1)).join('')
+
+let initials = [firstName, middleName, lastName].map(name => name.charAt(0)).join('')
+
+/* 
+There are more efficient ways of implementing the solution, however these concepts haven't been covered yet
+In these scenarios the slice and charAt have been implemented through a map
+
+let initials = [firstName, middleName, lastName].map(name => name.slice(0,1)).join('')
+let initials = [firstName, middleName, lastName].map(name => name.charAt(0)).join('')
+
+*/
 
 // https://www.google.com/search?q=get+first+character+of+string+mdn
 
-console.log(initials);
+console.log(initials); // display the output of initials to verify if successfuly executed