all the mandatory debug is done

The prediction and explanation were done

Author: saff-coder

Sprint-2/2-mandatory-debug/0.js

@@ -1,14 +1,20 @@
 // Predict and explain first...
 
-// =============> write your prediction here
+// =============> console.log will print the result because log()will write the message to the console.
+//
 
 function multiply(a, b) {
   console.log(a * b);
 }
 
 console.log(`The result of multiplying 10 and 32 is ${multiply(10, 32)}`);
 
-// =============> write your explanation here
-
+// =============> When testing the code in Node.js, the output was  320 without the message because it was undefined "The result of multiplying 10 and 32 is undefined".
+//we need to use return to store the result then print it out. 
 // Finally, correct the code to fix the problem
-//  =============> write your new code here
+//  =============> // Corrected Code:
+function multiply(a, b) {
+  return a * b; // Use 'return' instead of 'console.log'
+}
+console.log(`The result of multiplying 10 and 32 is ${multiply(10, 32)}`);
+

Sprint-2/2-mandatory-debug/1.js

@@ -1,5 +1,5 @@
 // Predict and explain first...
-//  =============> write your prediction here
+//  =============> i think there will be and error message because at doesn't show what value to return so it will be undefined.
 
 function sum(a, b) {
   return;
@@ -8,6 +8,10 @@ function sum(a, b) {
 
 console.log(`The sum of 10 and 32 is ${sum(10, 32)}`);
 
-// =============> write your explanation here
+// ============= it should be in the same line after return statement to return the value
 // Finally, correct the code to fix the problem
-//  =============> write your new code here
+//  =============> corrected code:
+function sum(a, b) {
+  return a + b;
+}
+console.log(`The sum of 10 and 32 is ${sum(10, 32)}`);

Sprint-2/2-mandatory-debug/2.js

@@ -1,7 +1,7 @@
 // Predict and explain first...
 
 // Predict the output of the following code:
-// =============> Write your prediction here
+// =============> I predict that the code might not work because I am declaring num outside the function also I am giving num a constant value means it will always be 103
 
 const num = 103;
 
@@ -14,11 +14,19 @@ console.log(`The last digit of 105 is ${getLastDigit(105)}`);
 console.log(`The last digit of 806 is ${getLastDigit(806)}`);
 
 // Now run the code and compare the output to your prediction
-// =============> write the output here
+// =============> the code worked but the answer was 3 i predicted an error message.
 // Explain why the output is the way it is
-// =============> write your explanation here
+// =============> the output was 3 because at the beginning  it we declared that num value as 103
 // Finally, correct the code to fix the problem
-// =============> write your new code here
+// =============> corrected code is running the code without giving num any value  and add num in the function 
+
+function getLastDigit(num) {
+  return num.toString().slice(-1);
+}
+
+console.log(`The last digit of 42 is ${getLastDigit(42)}`);
+console.log(`The last digit of 105 is ${getLastDigit(105)}`);
+console.log(`The last digit of 806 is ${getLastDigit(806)}`);
 
 // This program should tell the user the last digit of each number.
-// Explain why getLastDigit is not working properly - correct the problem
+// Explain why getLastDigit is not working properly - it was not working at the start because every time we run the code would slice the last number of the 103 because we declared num as a constant with value 103