feat(genai): update thinking model name

Add new model name.

Author: msampathkumar

genai/text_generation/thinking_textgen_with_txt.py

@@ -16,48 +16,55 @@
 def generate_content() -> str:
     # [START googlegenaisdk_thinking_textgen_with_txt]
     from google import genai
-    from google.genai.types import HttpOptions
 
-    client = genai.Client(http_options=HttpOptions(api_version="v1"))
+    client = genai.Client()
     response = client.models.generate_content(
-        model="gemini-2.0-flash-thinking-exp-01-21",
+        model="gemini-2.5-pro-exp-03-25",
         contents="solve x^2 + 4x + 4 = 0",
     )
     print(response.text)
-    # Example response:
-    #     To solve the equation x^2 + 4x + 4 = 0, we can use several methods.
+    # Example Response:
+    #     Okay, let's solve the quadratic equation x² + 4x + 4 = 0.
     #
-    #     **Method 1: Factoring**
+    #     There are a few ways to solve this:
     #
-    #     We look for two numbers that multiply to 4 (the constant term) and add to 4 (the coefficient of the x term).
-    #     These two numbers are 2 and 2 because 2 * 2 = 4 and 2 + 2 = 4.
-    #     Therefore, we can factor the quadratic expression as:
-    #     (x + 2)(x + 2) = 0
-    #     This can also be written as:
-    #     (x + 2)^2 = 0
+    #     **Method 1: Factoring**
     #
-    #     To solve for x, we set the factor (x + 2) equal to zero:
-    #     x + 2 = 0
-    #     Subtract 2 from both sides:
-    #     x = -2
+    #     1.  **Look for two numbers** that multiply to the constant term (4) and add up to the coefficient of the x term (4).
+    #         *   The numbers are 2 and 2 (since 2 * 2 = 4 and 2 + 2 = 4).
+    #     2.  **Factor the quadratic** using these numbers:
+    #         (x + 2)(x + 2) = 0
+    #         This can also be written as:
+    #         (x + 2)² = 0
+    #     3.  **Set the factor equal to zero** and solve for x:
+    #         x + 2 = 0
+    #         x = -2
     #
-    #     **Method 2: Quadratic Formula**
+    #     This type of solution, where the factor is repeated, is called a repeated root or a root with multiplicity 2.
     #
-    #     The quadratic formula for an equation of the form ax^2 + bx + c = 0 is given by:
-    #     x = [-b ± sqrt(b^2 - 4ac)] / (2a)
+    #     **Method 2: Using the Quadratic Formula**
     #
-    #     ...
+    #     The quadratic formula solves for x in any equation of the form ax² + bx + c = 0:
+    #     x = [-b ± √(b² - 4ac)] / 2a
     #
+    #     1.  **Identify a, b, and c** in the equation x² + 4x + 4 = 0:
+    #         *   a = 1
+    #         *   b = 4
+    #         *   c = 4
+    #     2.  **Substitute these values into the formula:**
+    #         x = [-4 ± √(4² - 4 * 1 * 4)] / (2 * 1)
+    #     3.  **Simplify:**
+    #         x = [-4 ± √(16 - 16)] / 2
+    #         x = [-4 ± √0] / 2
+    #         x = [-4 ± 0] / 2
+    #     4.  **Calculate the result:**
+    #         x = -4 / 2
+    #         x = -2
     #
-    #     All three methods yield the same solution, x = -2.
-    #     This is a repeated root, which is expected since the discriminant (b^2 - 4ac) is 0.
+    #     Both methods give the same solution.
     #
-    #     To check our solution, we substitute x = -2 back into the original equation:
-    #     (-2)^2 + 4(-2) + 4 = 4 - 8 + 4 = 0
-    #     The equation holds true, so our solution is correct.
-
-    #     Final Answer: The final answer is $\boxed{-2}$
-
+    #     **Answer:**
+    #     The solution to the equation x² + 4x + 4 = 0 is **x = -2**.
     # [END googlegenaisdk_thinking_textgen_with_txt]
     return response.text