Update README.md

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Author: eszmw

README.md

@@ -62,7 +62,7 @@ MATLAB® is used throughout. Tools from the Symbolic Math Toolbox™ are used fr
 | [FundamentalTheorem.mlx](https://matlab.mathworks.com/open/github/v1?repo=MathWorks-Teaching-Resources/Calculus-Integrals&project=Integrals.prj&file=Scripts/FundamentalTheorem.mlx) <br> <img src="Images/Ski-Area.png" width="135" alt="Distance traveled by skier"> <br>  | [Visualizing the FTC](https://matlab.mathworks.com/open/github/v1?repo=MathWorks-Teaching-Resources/Calculus-Integrals&project=Integrals.prj&file=Scripts/FundamentalTheoremViz.mlx) <br> <img src="Images/FTC-generated.png" width="135" alt="Signed area under a curve"> <br>  |    - explain the fundamental theorem of calculus. <br> - see why the Fundamental Theorem of Calculus makes sense graphically. <br> - develop computational fluency for definite integrals involving linear and rational combinations of powers, sines, cosines, exponentials and natural logarithms. <br>  | [Apply the Fundamental Theorem of Calculus](https://matlab.mathworks.com/open/github/v1?repo=MathWorks-Teaching-Resources/Calculus-Integrals&project=Integrals.prj&file=Scripts/FundamentalTheoremPractice.mlx) <br> $\displaystyle {\int_1^3 \frac{1}{w^2 }\;dw=-\frac{1}{3}+1=\frac{2}{3}}$ <br>   | 
 | [Riemann.mlx](https://matlab.mathworks.com/open/github/v1?repo=MathWorks-Teaching-Resources/Calculus-Integrals&project=Integrals.prj&file=Scripts/Riemann.mlx) <br> <img src="Images/animSolar.gif" width="135" alt="Better approximation with smaller rectangles"> <br>  | [Visualizing Riemann Sums](https://matlab.mathworks.com/open/github/v1?repo=MathWorks-Teaching-Resources/Calculus-Integrals&project=Integrals.prj&file=Scripts/RiemannViz.mlx) <br> <img src="Images/AreaUnderCurve.png" width="135" alt="Approximation by rectangles"> <br>  | - explain and apply the different approximations computed by a left\-endpoint, right\-endpoint, midpoint, maximum, or minimum method of selecting a height value in a Riemann sum. <br>  | - explain and apply the trapezoidal approximation. <br> - explain why increasing the number of intervals in an approximation will decrease the error. <br> - discuss the implications for applying calculus in applications with values that are discrete or continuous. <br>   |
 | [Substitution.mlx](https://matlab.mathworks.com/open/github/v1?repo=MathWorks-Teaching-Resources/Calculus-Integrals&project=Integrals.prj&file=Scripts/Substitution.mlx) <br> <img src="Images/SubstIm.png" width="135" alt="f(flower)"> <br>  | [Visualizing Substitution](https://matlab.mathworks.com/open/github/v1?repo=MathWorks-Teaching-Resources/Calculus-Integrals&project=Integrals.prj&file=Scripts/SubstitutionViz.mlx) <br> <img src="Images/animSubst.gif" width="135" alt="Animation of dx and du"> <br>  | - explain what the method of substitution is and how it works. <br> - develop fluency with computing integrals of combinations of powers, sines, cosines, exponentials and logarithms that are solvable <br>by substitution by hand. <br> - see a graphical understanding of the method of substitution. <br>  | [Apply the method of substitution](https://matlab.mathworks.com/open/github/v1?repo=MathWorks-Teaching-Resources/Calculus-Integrals&project=Integrals.prj&file=Scripts/SubstitutionPractice.mlx) <br> $\displaystyle {\int \frac{\cos \left(\ln (t)+1\right)}{t}\;dt=\sin \left(\ln (t)+1\right)+C}$ <br>   |  
-| [ByParts.mlx](https://matlab.mathworks.com/open/github/v1?repo=MathWorks-Teaching-Resources/Calculus-Integrals&project=Integrals.prj&file=Scripts/ByParts.mlx) <br> <img src="Images/IBP.png" width="135" alt="Geometric integration by parts"> <br>  | [Visualizing Integration by Parts](.Scripts/ByPartsViz.mlx) <br> <img src="Images/ibp-generated.png" width="135" alt="Integration horizontally and vertically"> <br>  |  - explain what the method of integration by parts is and how it works. <br> - develop fluency with computing integrals involving powers, sines, cosines, exponentials and logarithms that are solvable by integration by <br>parts by hand. <br> - see a graphical understanding of the integration by parts formula. <br>  | [Apply the method of integration by parts](https://matlab.mathworks.com/open/github/v1?repo=MathWorks-Teaching-Resources/Calculus-Integrals&project=Integrals.prj&file=Scripts/ByPartsPractice.mlx) <br> $\displaystyle {\int y^2 e^y \;dy=y^2 e^y -2ye^y +2e^y +C}$ <br> &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; $\displaystyle =(y^2 -2y+2)e^y +C$ <br>   | 
+| [ByParts.mlx](https://matlab.mathworks.com/open/github/v1?repo=MathWorks-Teaching-Resources/Calculus-Integrals&project=Integrals.prj&file=Scripts/ByParts.mlx) <br> <img src="Images/IBP.png" width="135" alt="Geometric integration by parts"> <br>  | [Visualizing Integration by Parts](https://matlab.mathworks.com/open/github/v1?repo=MathWorks-Teaching-Resources/Calculus-Integrals&project=Integrals.prj&file=Scripts/ByPartsViz.mlx) <br> <img src="Images/ibp-generated.png" width="135" alt="Integration horizontally and vertically"> <br>  |  - explain what the method of integration by parts is and how it works. <br> - develop fluency with computing integrals involving powers, sines, cosines, exponentials and logarithms that are solvable by integration by <br>parts by hand. <br> - see a graphical understanding of the integration by parts formula. <br>  | [Apply the method of integration by parts](https://matlab.mathworks.com/open/github/v1?repo=MathWorks-Teaching-Resources/Calculus-Integrals&project=Integrals.prj&file=Scripts/ByPartsPractice.mlx) <br> $\displaystyle {\int y^2 e^y \;dy=y^2 e^y -2ye^y +2e^y +C}$ <br> &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; $\displaystyle =(y^2 -2y+2)e^y +C$ <br>   | 
 
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