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#0019 findMinAndMaxNumber (L-B)
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## Problem
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Given an array of numbers, find the highest and lowest numbers in the array.
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## Test Cases
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- let numbers = [5, 3, 8, 2, 9]; // Min: 2, Max: 9
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- let numbers = [4, 10, 18, 2, 3]; // Min: 2, Max: 18
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- let numbers = [0, 100, 8, 21, 39]; // Min: 0, Max: 100
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## Solution
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```javascript
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let numbers = [5, 3, 8, 2, 9];
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let min = numbers[0];
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let max = numbers[0];
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for (let i = 0; i < numbers.length; i++) {
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if (numbers[i] < min) {
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min = numbers[i];
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}
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if (numbers[i] > max) {
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max = numbers[i];
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}
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}
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console.log(`Min: ${min}, Max: ${max}`);
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```
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## How it works
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- We start a `for` loop that iterates over each element of the `numbers` array.
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- Inside the loop, we check if the current element is less than the current value of `min`. If it is, we update `min` to the current element. This way, after the loop has finished executing, `min` will hold the smallest value in the numbers array.
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- We also check if the current element is greater than the current value of `max`. If it is, we update `max` to the current element. This way, after the loop has finished executing, `max` will hold the largest value in the `numbers` array.
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## References
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- [MDN](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/for)
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- [Wikipedia](https://en.wikipedia.org/wiki/For_loop)
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- [freeCodeCamp](https://www.freecodecamp.org/news/javascript-loops-explained-for-loop-for/)
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## Problem Added By
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- [GitHub](https://github.com/gabrysia97)
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## Contributing
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Pull requests are welcome. For major changes, please open an issue first to discuss what you would like to change.
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Please make sure to update tests as appropriate.
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let numbers = [5, 3, 8, 2, 9];
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let min = numbers[0];
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let max = numbers[0];
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for (let i = 0; i < numbers.length; i++) {
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if (numbers[i] < min) {
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min = numbers[i];
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}
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if (numbers[i] > max) {
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max = numbers[i];
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}
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}
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console.log(`Min: ${min}, Max: ${max}`);

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