Match the correct dictionary name for English words

Author: robotmlg

tests/zxcvbn_test.py

@@ -23,4 +23,16 @@ def test_long_password():
     input_ = None
     password = "weopiopdsjmkldjvoisdjfioejiojweopiopdsjmkldjvoisdjfioejiojweopiopdsjmkldjvoisdjfioejiojweopiopdsjmkldjvoisdjfioejiojweopiopdsjmkldjvoisdjfioejiojweopiopdsjmkldjvoisdjfioejiojweopiopdsjmkldjvoisdjfioejiojweopiopdsjmkldjvoisdjfioejiojweopiopdsjmkldjvoisdjfioejiojweopiopdsjmkldjvoisdjfioejiojweopiopdsjmkldjvoisdjfioej"
 
-    zxcvbn(password, user_inputs=[input_])
+    zxcvbn(password, user_inputs=[input_])
+
+
+def test_dictionary_password():
+    # return the correct error message for a english match
+    input_ = None
+    password = "musculature"
+
+    result = zxcvbn(password, user_inputs=[input_])
+
+    assert result["feedback"]["warning"] == \
+           "A word by itself is easy to guess.", \
+           "Gives specific error for single-word passwords"

zxcvbn/feedback.py

@@ -103,7 +103,7 @@ def get_dictionary_match_feedback(match, is_sole_match):
                 warning = _('This is a very common password.')
         elif match['guesses_log10'] <= 4:
             warning = _('This is similar to a commonly used password.')
-    elif match['dictionary_name'] == 'english':
+    elif match['dictionary_name'] == 'english_wikipedia':
         if is_sole_match:
             warning = _('A word by itself is easy to guess.')
     elif match['dictionary_name'] in ['surnames', 'male_names',