EPP value not read correctly #141
Description
Logic should be:
IF 0x774[42] is '1' AND 0x774[60] is '0'
THEN
get EPP from 0x772 (package)
ELSE
get EPP from 0x774 (cpu)
{{ message }}
Logic should be:
IF 0x774[42] is '1' AND 0x774[60] is '0'
THEN
get EPP from 0x772 (package)
ELSE
get EPP from 0x774 (cpu)