Make go to definition go to the constraint's properties for object literals in argument positions #62361
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…terals in argument positions
| None = 0, | ||
| Signature = 1 << 0, // Obtaining contextual signature | ||
| NoConstraints = 1 << 1, // Don't obtain type variable constraints | ||
| IgnoreNodeInferences = 1 << 2, // Ignore inference to current node and parent nodes out to the containing call for, for example, completions |
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As shown by this PR, this mechanism is handy for other things than just completions - so I decided to rename it.
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| if (contextualType) { | ||
| return flatMap(getPropertySymbolsFromContextualType(element, typeChecker, contextualType, /*unionSymbolOk*/ false), propertySymbol => getDefinitionFromSymbol(typeChecker, propertySymbol, node)); | ||
| let properties = getPropertySymbolsFromContextualType(element, typeChecker, contextualType, /*unionSymbolOk*/ false); | ||
| if (properties.length === 1) { |
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Is there no way that this would ever apply if there were more than one symbol here? Like, can the definition be both the constraint but also something else via a union?
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It could come from multiple sources. This is just me using a conservative approach that covers the majority of use cases. I don't see a reason why it wouldn't be OK to change the algorithm to:
- check if
propertiescontain a "self declaration" - if yes then get contextual type with
ContextFlags.IgnoreNodeInferences - if we get some results then get
withoutNodeInferencesPropertiesand if there are some then filter out self-declaration and concat both arrays
This should leave all potential meaningful definitions in the result. WDYT?
A simple playground for experimenting with how TypeScript behaves today in presence of unions: TS playground
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I feel like it must be better to not hardcode "exactly one property", but then again I don't know what the change I suggested looks like in code.
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