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How to give arguments for Read Csv As Dictionary in robot framework #65

@jayajothig

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@jayajothig

Hi ,
I am using RIDE 1.7.3.1 running on Python 3.7.5. Iam doing migration process frpm python 27 to python 37 . in python 27 i have used the key word read csv file to associative to Read the csv file as a dictinary. For example if my csv file is

id,name,age,height,weight
1,Alice,20,62,120.6
2,Freddie,21,74,190.6
3,Bob,17,68,120.0

i want an output like the following

{'age': '20', 'height': '62', 'id': '1', 'weight': '120.6', 'name': 'Alice'}
{'age': '21', 'height': '74', 'id': '2', 'weight': '190.6', 'name': 'Freddie'}
{'age': '17', 'height': '68', 'id': '3', 'weight': '120.0', 'name': 'Bob'}

In python 37 csvlib 1.0.0 is only supported.
it contains the following keywords

Read CSV As Single List
Read CSV As List
Read CSV As Dictionary

I am using the following libraries.

pip freeze

Appium-Python-Client==0.48
bcrypt==3.1.7
beautifulsoup4==4.8.1
certifi==2019.9.11
cffi==1.13.2
chardet==3.0.4
coverage==4.5.4
cryptography==2.8
decorator==4.4.1
docutils==0.15.2
idna==2.8
importlib-metadata==0.23
jsonpatch==1.24
jsonpath-rw==1.4.0
jsonpath-rw-ext==1.2.2
jsonpointer==2.0
kitchen==1.2.6
more-itertools==7.2.0
numpy==1.17.4
oauthlib==3.1.0
paramiko==2.6.0
pbr==5.4.3
Pillow==6.2.1
pluggy==0.13.0
ply==3.11
py==1.8.0
pycparser==2.19
Pygments==2.4.2
PyNaCl==1.3.0
PyPubSub==3.3.0
pywin32==227
requests==2.22.0
requests-oauthlib==1.3.0
robotframework==3.1.2
robotframework-appiumlibrary==1.5.0.4
robotframework-csvlib==1.0.0
robotframework-extendedrequestslibrary==0.5.5
robotframework-ftplibrary==1.6
robotframework-httplibrary==0.4.2
robotframework-jsonlibrary==0.3.1
robotframework-requests==0.6.2
robotframework-ride==1.7.3.1
robotframework-selenium2library==3.0.0
robotframework-seleniumlibrary==4.1.0
robotframework-sshlibrary==3.4.0
robotframeworklexer==1.1
scp==0.13.2
selenium==3.141.0
six==1.13.0
soupsieve==1.9.5
tox==3.0.0
urllib3==1.25.7
virtualenv==16.7.7
waitress==1.3.1
WebOb==1.8.5
WebTest==2.0.33
wxPython==4.0.7.post2
zipp==0.6.0

Could you give the solution to get the output like above.

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