build: skip build-ci on run-ci

legendecas · legendecas · commit 6eb4f78e210c · 2025-12-15T13:05:07.000Z
When run `make run-ci` with CONFIG_FLAGS only set in prior
`make build-ci`, `make run-ci` will try to rebuild everything, instead
of re-use the built result from prior `make build-ci`.
diff --git a/Makefile b/Makefile
@@ -638,7 +638,7 @@ build-ci: ## Build everything (CI).
 #
 # Using -j1 as the sub target in `test-ci` already have internal parallelism.
 # Refs: https://github.com/nodejs/node/pull/23733
-run-ci: build-ci ## Build and run all tests (CI).
+run-ci: ## Run all tests (CI).
 	$(MAKE) test-ci -j1
 
 .PHONY: test-release

Original file line number	Diff line number	Diff line change
`@@ -638,7 +638,7 @@ build-ci: ## Build everything (CI).`
`638`	`638`	`#`
`639`	`639`	# Using -j1 as the sub target in `test-ci` already have internal parallelism.
`640`	`640`	`# Refs: https://github.com/nodejs/node/pull/23733`
`641`		`-run-ci: build-ci ## Build and run all tests (CI).`
	`641`	`+run-ci: ## Run all tests (CI).`
`642`	`642`	`$(MAKE) test-ci -j1`
`643`	`643`
`644`	`644`	`.PHONY: test-release`