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it's not really about fidget anyway
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posts/2025/04/prospero-in-rpython.md

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@@ -444,7 +444,7 @@ In this case, the "demanded bits" of the `byteswap(a)` expression are
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`0b0...011111111`, which inversely means that we don't care about the upper 56
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bits. Therefore the whole expression can be optimized to `a >> 56`.
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For Fidget, we can observe that for the resulting pixel values, the value of
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For the Prospero challenge, we can observe that for the resulting pixel values, the value of
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the result is not used at all, only its sign. Essentially, every program ends
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implicitly with a `sign` operation that returns `0.0` for negative values and
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`1.0` for positive values. For clarity, I will show this `sign` operation in

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