more accurate help(help) output

Author: adqm

Lib/pydoc.py

@@ -2117,21 +2117,25 @@ def helphelp(self, is_interactive=False):
             pager(textwrap.dedent("""\
                 help - Interactive Help
                 =======================
+
                 The built-in help function implements an interactive help utility.  You
                 can make use of it in a few different ways:
 
                 * Calling help() with no arguments starts an interactive help session.
 
-                * Calling help(x) will have one of two behaviors depending on the type
-                  of the argument:
+                * The behavior of help(x) depends on the type of the argument:
 
                     * If x is a string, help(x) provides information about the given
                       topic.  For example, help("class") will provide information about
                       the "class" keyword, and help("math.sqrt") will provide
                       information about the "math.sqrt" function.
 
-                    * If x is not a string, help(x) prints information about x's type.
-                      For example, help(42) will provide information about the int type.
+                    * If x is a class or a built-in type, help(x) provides information
+                      about that type.  For example, help(str) will provide information
+                      about the str type.
+
+                    * Otherwise, help(x) provides information about x's type. For
+                      example, help(42) will provide information about the int type.
             """))
 
     def intro(self):