Correct operator precedence for "@" in m_expr

Author: guan404ming

Doc/reference/expressions.rst

@@ -1373,7 +1373,7 @@ from the power operator, there are only two levels, one for multiplicative
 operators and one for additive operators:
 
 .. productionlist:: python-grammar
-   m_expr: `u_expr` | `m_expr` "*" `u_expr` | `m_expr` "@" `m_expr` |
+   m_expr: `u_expr` | `m_expr` "*" `u_expr` | `m_expr` "@" `u_expr` |
          : `m_expr` "//" `u_expr` | `m_expr` "/" `u_expr` |
          : `m_expr` "%" `u_expr`
    a_expr: `m_expr` | `a_expr` "+" `m_expr` | `a_expr` "-" `m_expr`

Lib/pydoc_data/topics.py

@@ -919,7 +919,7 @@ class and instance attributes applies as for regular assignments.
 levels, one for multiplicative operators and one for additive
 operators:
 
-   m_expr: u_expr | m_expr "*" u_expr | m_expr "@" m_expr |
+   m_expr: u_expr | m_expr "*" u_expr | m_expr "@" u_expr |
            m_expr "//" u_expr | m_expr "/" u_expr |
            m_expr "%" u_expr
    a_expr: m_expr | a_expr "+" m_expr | a_expr "-" m_expr