Add solution and test-cases for problem 2593

leetcode/2501-2600/2593.Find-Score-of-an-Array-After-Marking-All-Elements/README.md

@@ -0,0 +1,44 @@
+# [2593.Find Score of an Array After Marking All Elements][title]
+
+## Description
+You are given an array `nums` consisting of positive integers.
+
+Starting with `score = 0`, apply the following algorithm:
+
+- Choose the smallest integer of the array that is not marked. If there is a tie, choose the one with the smallest index.
+- Add the value of the chosen integer to `score`.
+- Mark **the chosen element and its two adjacent elements if they exist**.
+- Repeat until all the array elements are marked.
+
+Return the score you get after applying the above algorithm.
+
+**Example 1:**
+
+```
+Input: nums = [2,1,3,4,5,2]
+Output: 7
+Explanation: We mark the elements as follows:
+- 1 is the smallest unmarked element, so we mark it and its two adjacent elements: [2,1,3,4,5,2].
+- 2 is the smallest unmarked element, so we mark it and its left adjacent element: [2,1,3,4,5,2].
+- 4 is the only remaining unmarked element, so we mark it: [2,1,3,4,5,2].
+Our score is 1 + 2 + 4 = 7.
+```
+
+**Example 2:**
+
+```
+Input: nums = [2,3,5,1,3,2]
+Output: 5
+Explanation: We mark the elements as follows:
+- 1 is the smallest unmarked element, so we mark it and its two adjacent elements: [2,3,5,1,3,2].
+- 2 is the smallest unmarked element, since there are two of them, we choose the left-most one, so we mark the one at index 0 and its right adjacent element: [2,3,5,1,3,2].
+- 2 is the only remaining unmarked element, so we mark it: [2,3,5,1,3,2].
+Our score is 1 + 2 + 2 = 5.
+```
+
+## 结语
+
+如果你同我一样热爱数据结构、算法、LeetCode，可以关注我 GitHub 上的 LeetCode 题解：[awesome-golang-algorithm][me]
+
+[title]: https://leetcode.com/problems/find-score-of-an-array-after-marking-all-elements
+[me]: https://github.com/kylesliu/awesome-golang-algorithm

leetcode/2501-2600/2593.Find-Score-of-an-Array-After-Marking-All-Elements/Solution.go

@@ -1,5 +1,59 @@
 package Solution
 
-func Solution(x bool) bool {
+import "container/heap"
+
+type item2593 struct {
+	v, i int
+}
+
+type heap2593 []item2593
+
+func (h *heap2593) Len() int {
+	return len(*h)
+}
+
+func (h *heap2593) Swap(i, j int) {
+	(*h)[i], (*h)[j] = (*h)[j], (*h)[i]
+}
+func (h *heap2593) Less(i, j int) bool {
+	a, b := (*h)[i], (*h)[j]
+	if a.v == b.v {
+		return a.i < b.i
+	}
+	return a.v < b.v
+}
+
+func (h *heap2593) Push(x any) {
+	*h = append(*h, x.(item2593))
+}
+func (h *heap2593) Pop() any {
+	old := *h
+	l := len(old)
+	x := old[l-1]
+	*h = old[:l-1]
 	return x
 }
+
+func Solution(nums []int) int64 {
+	l := len(nums)
+	used := make([]bool, l)
+	h := &heap2593{}
+	for i := range l {
+		heap.Push(h, item2593{v: nums[i], i: i})
+	}
+	ans := int64(0)
+	for h.Len() > 0 {
+		top := heap.Pop(h).(item2593)
+		if used[top.i] {
+			continue
+		}
+		ans += int64(top.v)
+		if top.i-1 >= 0 {
+			used[top.i-1] = true
+		}
+		if top.i+1 < l {
+			used[top.i+1] = true
+		}
+	}
+	return ans
+}

leetcode/2501-2600/2593.Find-Score-of-an-Array-After-Marking-All-Elements/Solution_test.go

@@ -10,12 +10,11 @@ func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
 		name   string
-		inputs bool
-		expect bool
+		inputs []int
+		expect int64
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", []int{2, 1, 3, 4, 5, 2}, 7},
+		{"TestCase", []int{2, 3, 5, 1, 3, 2}, 5},
 	}
 
 	//	开始测试
@@ -30,10 +29,10 @@ func TestSolution(t *testing.T) {
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }