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Original file line number Diff line number Diff line change
@@ -1,28 +1,46 @@
# [3264.Final Array State After K Multiplication Operations I][title]

> [!WARNING|style:flat]
> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)

## Description
You are given an integer array `nums`, an integer `k`, and an integer `multiplier`.

You need to perform `k` operations on `nums`. In each operation:

- Find the **minimum** value `x` in `nums`. If there are multiple occurrences of the minimum value, select the one that appears **first**.
- Replace the selected minimum value `x` with `x * multiplier`.

Return an integer array denoting the final state of `nums` after performing all `k` operations.

**Example 1:**

```
Input: a = "11", b = "1"
Output: "100"
```
Input: nums = [2,1,3,5,6], k = 5, multiplier = 2

## 题意
> ...
Output: [8,4,6,5,6]

## 题解
Explanation:

### 思路1
> ...
Final Array State After K Multiplication Operations I
```go
Operation Result
After operation 1 [2, 2, 3, 5, 6]
After operation 2 [4, 2, 3, 5, 6]
After operation 3 [4, 4, 3, 5, 6]
After operation 4 [4, 4, 6, 5, 6]
After operation 5 [8, 4, 6, 5, 6]
```

**Example 2:**

```
Input: nums = [1,2], k = 3, multiplier = 4

Output: [16,8]

Explanation:

Operation Result
After operation 1 [4, 2]
After operation 2 [4, 8]
After operation 3 [16, 8]
```

## 结语

Expand Down
Original file line number Diff line number Diff line change
@@ -1,5 +1,50 @@
package Solution

func Solution(x bool) bool {
import "container/heap"

type heap3264 [][2]int

func (h *heap3264) Len() int {
return len(*h)
}

func (h *heap3264) Swap(i, j int) {
(*h)[i], (*h)[j] = (*h)[j], (*h)[i]
}

func (h *heap3264) Less(i, j int) bool {
a, b := (*h)[i], (*h)[j]
if a[1] == b[1] {
return a[0] < b[0]
}
return a[1] < b[1]
}

func (h *heap3264) Push(x any) {
*h = append(*h, x.([2]int))
}

func (h *heap3264) Pop() any {
old := *h
l := len(old)
x := old[l-1]
*h = old[:l-1]
return x
}

func Solution(nums []int, k int, multiplier int) []int {
h := &heap3264{}
for i := range nums {
heap.Push(h, [2]int{i, nums[i]})
}
for ; k > 0; k-- {
top := heap.Pop(h).([2]int)
top[1] *= multiplier
heap.Push(h, top)
}
for h.Len() > 0 {
top := heap.Pop(h).([2]int)
nums[top[0]] = top[1]
}
return nums
}
Original file line number Diff line number Diff line change
Expand Up @@ -9,31 +9,31 @@ import (
func TestSolution(t *testing.T) {
// 测试用例
cases := []struct {
name string
inputs bool
expect bool
name string
nums []int
k, multiplier int
expect []int
}{
{"TestCase", true, true},
{"TestCase", true, true},
{"TestCase", false, false},
{"TestCase1", []int{2, 1, 3, 5, 6}, 5, 2, []int{8, 4, 6, 5, 6}},
{"TestCase2", []int{1, 2}, 3, 4, []int{16, 8}},
}

// 开始测试
for i, c := range cases {
t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
got := Solution(c.inputs)
got := Solution(c.nums, c.k, c.multiplier)
if !reflect.DeepEqual(got, c.expect) {
t.Fatalf("expected: %v, but got: %v, with inputs: %v",
c.expect, got, c.inputs)
t.Fatalf("expected: %v, but got: %v, with inputs: %v %v %v",
c.expect, got, c.nums, c.k, c.multiplier)
}
})
}
}

// 压力测试
// 压力测试
func BenchmarkSolution(b *testing.B) {
}

// 使用案列
// 使用案列
func ExampleSolution() {
}
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