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[dyn_stack] Replace np.sum(a * b) with a @ b #210

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Merged
mmcky merged 2 commits into from
Aug 5, 2025
Merged

[dyn_stack] Replace np.sum(a * b) with a @ b #210

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Replace np.sum(a * b) with a @ b
suda-yuga Jul 5, 2025
f65757a
Merge branch 'main' into dyn_stack_npsum
mmcky Aug 5, 2025
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6 changes: 3 additions & 3 deletions lectures/dyn_stack.md
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Original file line number Diff line number Diff line change
Expand Up @@ -1043,7 +1043,7 @@ We'll compute it two ways and get the same answer.
In addition to being a useful check on the accuracy of our coding, computing things in these two ways helps us think about the structure of the problem.

```{code-cell} python3
v_leader_forward = np.sum(βs * π_leader)
v_leader_forward = βs @ π_leader
v_leader_direct = -yt[:, 0].T @ P @ yt[:, 0]

# Display values
Expand Down Expand Up @@ -1380,8 +1380,8 @@ u2 = (- F2 @ z).flatten()
π_1 = p * q1 - γ * (u1) ** 2
π_2 = p * q2 - γ * (u2) ** 2

v1_forward = np.sum(βs * π_1)
v2_forward = np.sum(βs * π_2)
v1_forward = βs @ π_1
v2_forward = βs @ π_2

v1_direct = (- z[:, 0].T @ P1 @ z[:, 0])
v2_direct = (- z[:, 0].T @ P2 @ z[:, 0])
Expand Down
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