Fix the Variation Selector handling #278
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Fix the problem that the variable `i` was overwritten and the non-default UVS wasn't used when the default UVS exists.
devongovett
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May 25, 2022
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devongovett
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devongovett
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Thanks. Alternatively, you could make i within the if statement block scoped (via let), so it isn't overwritten?
| i = binarySearch(sel.defaultUVS, x => | ||
| codepoint < x.startUnicodeValue ? -1 : codepoint > x.startUnicodeValue + x.additionalCount ? +1 : 0 | ||
| ); | ||
| if (i !== -1) { |
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Should this be the opposite, i.e. i === -1?
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I'm sorry I didn't make it clear enough. My pull request fixes two problems.
- When the default UVS table exists and its entry not exists (
i === -1), the variableiwas overwriten and the non-default UVS isn't used. - When the default entry exists (
i !== -1), it means "the default glyph (the same glyph as base character) should be used" and checking the non-default UVS is unnecessary. By returning 0, the Variation Selector is ignored correctly here.
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A test would help understanding the issue and ensuring the fix is correct
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Fix the problem that the variable
iwas overwritten and the non-default UVS wasn't used when the default UVS exists.